Cell Backcolor

[User (Old forums)]

#13856 |

Hi,

Does anyone know if it’s possible to paint just one part of a cells backcolor?

Imported from legacy forums. Posted by Jeff_ (had 2719 views)

[User (Old forums)]

#13857

I don’t really understand what you mean by ‘painting just one part’. Could you explain some more?

Imported from legacy forums. Posted by Tommy (had 330 views)

[User (Old forums)]

#13858

Hi Tommy,

I try to explain it better.

In the grid we have the possibility to set the backcolor of the cells, but when you set the backcolor of a cell the cell is completly painted in that color.

What I want to know is if it’s possible to split a cell in two ore more parts and to set a different color for each part.

Here is an example of a cell I need.
http://www.bitmap.lu/grid.jpg

Sorry for my bad english.

Imported from legacy forums. Posted by Jeff_ (had 409 views)

[User (Old forums)]

#13859

You can do it, like this (the code below has not been tested):
1. Create a class that inherits from <b>Xceed.Grid.DataCell</b>:<code>public class MyDataCell : Xceed.Grid.DataCell
{
public MyDataCell() { }
public MyDataCell(string fieldName):base(fieldName) { }
public MyDataCell(MyDataCell template):base(template) { }
public MyDataCell(Column column):base(column) { }
protected override Cell CreateInstance() {
return new MyDataCell(this);
}
<b>protected override void PaintBackground(GridPaintEventArgs e) {
// here you put code to paint the background of the cell
}</b>
}</code>2. Create a class that inherits from <b>Xceed.Grid.DataRow</b>:<code>public class MyDataRow : Xceed.Grid.DataRow
{
public MyDataRow() { }
public MyDataRow(MyDataRow template):base(template) { }
public MyDataRow(RowSelector selector):base(selector) { }
protected override Row CreateInstance() {
return new MyDataRow(this);
}
protected override Cell CreateCell(Column column) {
return new MyDataCell(column);
}
}</code>3. Set the <b>DataRowTemplate</b> property of your GridControl to an instance of your custom DataRow class:<code>grid.DataRowTemplate = new MyDataRow();</code>

Imported from legacy forums. Posted by Tommy (had 3979 views)

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